# Tags: AND

Here is a dataset showing Project wise forecast of open opportunities.

1. Topic is the Project Name
2. Est. Close Date is the date by when the opportunity would be closed i.e. the project would be won from that Client
3. Duration is the time (in months) for which the project would run
4. Amount is the total amount that would be billed for that project

Clients are invoiced annually only. So in the example below:

1. Project ABC is for US\$1 million with a duration of 24 months and is expected to be closed in Oct. 2017.  We need to model the data to show the billing every 12 months.  So for ABC US\$500K would be billed in Oct-2017 and another US\$500K in Oct-2018.
2. Project GEF is for US\$2 million with a duration of 18 months and is expected to be closed in Feb. 2018. We need to model the data to show US\$1.3 million in Feb-2018 and another US\$666K in Feb-2019.  The monthly billing is US\$2 million divided by 18 and then multiplied by 12 - this amounts to US\$1.3 million.
 Topic Est. Close Date Duration (Months) Amount ABC 01-10-2017 24 1,000,000 GEF 01-02-2018 18 2,000,000 XYZ 01-03-2018 30 1,000,000

The expected result should look like this:

 Row Labels Oct-17 Feb-18 Mar-18 Oct-18 Feb-19 Mar-19 Mar-20 Total ABC 500,000 500,000 1,000,000 GEF 1,333,333 666,667 2,000,000 XYZ 400,000 400,000 200,000 1,000,000 Grand Total 500,000 1,333,333 400,000 500,000 666,667 400,000 200,000 4,000,000

I have solved this problem using Power Query and PowerPivot. You may download my solution workbook from here.

Here is a simple two column dataset which shows EmpID in column A and DateWorked in column B.  My objective is to filter the table to show those employees who worked ONLY on August 17 and August 18.  I'd like to exclude employees who:

1. Did not work on both these days; and
2. Worked on both these dates but also worked on other dates

A simple filter on the DatesWorked column with the criteria of August 17 and August 18, would return 7 employees.  This is clearly wrong because this will show employees who:

1. Worked on any of the two chosen dates; and
2. Worked on dates other than the two chosen dates

From Table 1, one can clearly observe that the correct result should be EmpID E.  Only EmpID E worked on August 17 and 18.  While others also worked on both these dates, they worked on other dates as well and should therefore be excluded.

The problem outlined above holds true for selections made via a slicer in a Pivot Table as well.  So this is a generic problem with a filter/slicer - conditions specified therein behave like OR conditions, not like AND conditions.

Base dataset

 EmpID DateWorked A 14-08-2017 A 15-08-2017 A 16-08-2017 A 17-08-2017 A 18-08-2017 B 15-08-2017 B 16-08-2017 B 18-08-2017 C 14-08-2017 C 15-08-2017 C 16-08-2017 C 17-08-2017 C 18-08-2017 D 14-08-2017 D 15-08-2017 D 16-08-2017 D 17-08-2017 D 18-08-2017 E 17-08-2017 E 18-08-2017 F 16-08-2017 F 17-08-2017 G 18-08-2017

Filtered dataset (after specifying the criteria as 17 Aug and 18 Aug)

 EmpID DateWorked A 17-08-2017 A 18-08-2017 B 18-08-2017 C 17-08-2017 C 18-08-2017 D 17-08-2017 D 18-08-2017 E 17-08-2017 E 18-08-2017 F 17-08-2017 G 18-08-2017

So the question is "How does one change the behavior of a filter/slicer from OR to AND?". To make things worse, the data is arranged as follows:

 EmpID DateWorked A 14/8/17;15/8/17;16/8/17;17/8/17;18/8/17 B 15/8/17;16/8/17;18/8/17 C 14/8/17;15/8/17;16/8/17;17/8/17;18/8/17 D 14/8/17;15/8/17;16/8/17;17/8/17;18/8/17 E 17/8/17;18/8/17 F 16/8/17;17/8/17 G 18-08-17

As you can see, there are multiple dates in a single cell separated by a ;.

You may refer to my Power Query and PowerPivot solution here.

Assume a two column dataset with Date in the first column and Price in the second one.  The purpose is to identify times to buy and sell - buying would be just after the lowest low is confirmed and sell before or just after the highest high is in place. Confirmation is achieved through crossover of moving averages. This data is being used in back testing buy and sell criteria.

Snapshot of base data

Snapshot of expected result

The Lowest Low is the lowest price that occurs before the next Highest High.  The Highest High is the highest price that occurs before the next Lowest Low..  2.77 is the lowest low after the highest high of 3.69 and 3.23 is highest high after the lowest low of 2.77.

You may refer to my solution in this workbook.

Scenario 1

In a Stock Broking business (Firm), Customers deposit margin money through cheques. Although cheques are received from customers at branches, clearing (realization) of the same normally takes 3-4 days.  On one hand, the Firm wishes to allow trading to the customers against the deposited cheques from the day it receives the cheque, on other hand there is a risk associated with this  i.e cheque may get dishonored and the Firm may incur huge financial losses because of allowing customers to trade in anticipation of the cheque realization. Hence, there is a trade off between customer centricity & Financial Risk management.

The Firm may decide to take a calculated risk in order to retain its customer centric approach (it is a delightful experience for customers if they get trading benefit against the deposited cheque instantly before realization). The Firm may decide to give the benefit of cheque which are below a set threshold amount (say 50,000) instantly and for cheques which are above threshold amount the credit will be given only after realization. Sometimes there are  multiple unrealized cheques deposited by one client but the Firm needs to cap the total benefit of unrealized cheques to 50,000 (partial benefit against any cheque is not possible i.e. either a cheque will be considered in full or not considered) E.g. if a customer deposits 3 cheques of 40,000 each then also the total instant benefit against all unrealized cheques shall be capped at 50,000 - hence only one cheques of 40,000 will be credited to customers ledger before realization.

Now the question here is with respect to selection of cheques to give best results i.e. maximum total below 50,000.  Consider the following example:

Cheque1: 55,000
Cheque2: 44,000
Cheque3: 28,000
Cheque4: 7,000
Cheque5: 6,500
Cheque6: 4,000
Cheque7: 3,000
Cheque8: 500

The Firm wants to identify the "Combination of cheques" which gives the maximum benefit to the Customer subject to a limit of 50,000.  The result should be cheques 3-8.  They add up to 49,000.

Here's another example:

Cheque1: 55,000
Cheque2: 45,000
Cheque3: 25,000
Cheque4: 5,000

The result here should be cheque 2 and 4.  They add up to 50,000.

Here are my thoughts:

1. I have assumed that the total number of cheques received from customer will be capped to 8.  This limit can be relaxed but processing will then take time.

2. Create all possible combinations of cheques which can be credited.  So, since no partial credit is allowed, the cheque can either be accepted in full or be rejected.  Hence the possible values can be 2 i.e. 1 (Accepted) or 0 (Rejected).

3. So if there are 8 cheques received from a certain customer, then there will be 2^8 i.e. 256 possible combinations.  This can also be computed by using the =PERMUTATIONA(2,8) formula.  I'd like to than Saurabh Gupta for sharing the formula to generate all these combinations.

4. After creating all possible combinations, add the cheque amount for each combination.

5. Scan this total column and highlight the one which is the largest value <= the threshold value i.e. 50,000.

You may refer to my solution in the Solution worksheet of this workbook.

Scenario 2

Here's another example.  Say, one has a list of numbers as shown below:

1072.94
1643.02
1248.09
2167.34
276.85
322.05
910.22
1146.39
56.50

Now one may want to know which combination of numbers adds up to or comes closest to 5115.52 (our lookup value).  If none of the combinations adds up exactly to the lookup value, then return the combination which adds to the largest value less then equal to the lookup value.  In the example above, the second, third and fourth add up to 5114.95.

You may find my solution in this workbook.

Assume a table which lists attendees for a Company's Annual day function.  In this Table, data for every attendee is shown on a separate row so if an employee attends the function with his/her spouse and three children, then there will be 5 rows for that employee.

The question is to determine the count of the following family configuration:

1. Employees only (those who attended without spouse and children); and
2. Employees, spouse and children (Family); and
3. Employees and spouse (no children); and
4. Employees and children (no spouse)

You may refer to my solution in this workbook.  I have solved this problem using:

1. MS Excel Formulas based on Set Theory and Venn Diagram; and
2. PowerPivot

Assume per diem travel rates vary by block of dates (from and to).  So, assume the per diem rate for travel dates between 26/2/2013 and 28/2/2013 is Rs. 78,000/day.  Likewise, if a person travels between 1/3/2013 and 25/3/2013, the per diem rate applicable is Rs. 70,000/day.  With different travel dates (from and to) specified per traveller, the task is to determine total travel expenses per individual.

You may refer to my solution in this workbook.

Given the following inputs/restrictions, one may want to compute the end date and time of a project:

1. Start date and time of the project; and
2. Official working hours; and
3. Lunch breaks hours

Furthermore, to add to the complication, one may have different National holidays and weekend days i.e. while for some, the weekend days may be Saturday and Sunday, for others it may be Friday and Saturday.

You may refer to both my solutions here

1. Given National holidays and where Saturday and Sunday are the weekend days - Download workbook.  This solution will work in all Excel versions

2. Given National holidays and where Friday and Saturday are the weekend days - Download workbook.  This solution will work only in Excel 2010 and higher versions.

Assume the following numbers in range C5:C22.  Heading is in cell C4.

Range C5:C7 - 11
Range C8:C11 - 14
Range C12:C13 - 23
Range C14-C19 - 56
Range C20-C22 - 78

One may want to colour cells for every change in number in range C5:C22 with the following two modifications:

1. Shading should be for alternate band of rows i.e. C5:C7 should be coloured, C8:C11 should not be coloured, C12:C13 should be coloured, C14:C19 should not be coloured and C20:C22 should be coloured.

2. Shading should vary with the range being filtered i.e. If range C5:C22 is filtered to exclude 14 and 56, then numbers 11 and 78 should be coloured i.e. range C5:C7 and C20:C22 should be coloured.

To accomplish this, try the following:

a. Select cell C5 and go to Home > Format > Conditional formatting > New Rule > Use a formula to determine which cells to format

b. In the formula box there, enter the following formula

=AND(ISODD(COUNT(1/FREQUENCY(IF(SUBTOTAL(3,OFFSET(C\$5,ROW(C\$5:C5)-ROW(C\$5),)),MATCH(C\$5:C5,C\$5:C5,0)),ROW(C\$5:C5)-ROW(C\$5)))),COUNT(1/FREQUENCY(IF(SUBTOTAL(3,OFFSET(C\$5,ROW(\$C\$5:\$C\$22)-ROW(C\$5),)),MATCH(\$C\$5:\$C\$22,\$C\$5:\$C\$22,0)),ROW(\$C\$5:\$C\$22)-ROW(C\$5)))>1)

c. Click on Format and select any Fill colour

d. Click on OK > OK > Apply

e. Copy cell C5, select range C6:C22 and right-click > Paste Special > Formats

With no filter in place, colouring will happen as mentioned in point 1 above.  Auto filter the range now on some values and the colour banding should change.

Depending upon customer requirements specified for width, thickness and length os material, extract a report showing all records from the master stock-list which meets the requirements.

The question and solution have been elaborately explained in this workbook.

The objective is to determine the quantity of stock (of a particular type) to be transferred from "Stock surplus" locations to "Stock deficient" ones.  If all the requirements cannot be met from one location, tap other locations.  The final output should show the location from where stock is being transferred.  Furthermore the order of determining "Stock transfer location" is descending order of stock available in "Stock surplus" locations.  Stock available in "Stock surplus" locations should be determined after setting off quantity already transferred to other locations.

For solving this problem, you will have to download and install the morefunc addin from here.  For instructions of installing the addin for Excel 2010, please refer point 4 of the following post.

You may refer to my solution in this workbook.